I had my Galaxie's 400 Modified bored .030 over it then displaced 406 cubic inches. It added about 1% to my engines size, so your 289 is now a 292. If you had a 302 it would be a 305.
2007-08-28 15:41:42
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answer #1
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answered by Marc 2
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the equation I have is diameter squared x .7854 x stroke x number of cylinders. Check it out let me know if it's right. it's been allot of years since I used it. A 289 30 over should be about a 292 cu in. you should be able to convert that to cubic centimeters
2007-08-28 15:58:18
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answer #2
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answered by frfiter 3
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Their are 61.13 cubic inches in a Liter. So at 289 ci your engine has 4.7 liters or 4700cc. A lot bigger than the 1600cc volkswagons driving around. Some car companies fudge the conversion and use 60 ci per liter to get a number that they prefer.
2007-08-28 15:51:20
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answer #3
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answered by Tomsriv 5
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Well, you can do it one of two ways:
Convert all linear measurements to metric, and then figure out the volume of 8 cylinders,
or,
Figure out the volume of 8 cylinders, then convert spatial measurements to metric. This is the one I am going to show below.
The original bore of a 289 is 4.00 cu. in. by 2.87 cu. in.
Your overbore would make your motors bore 4.03 cu. in.
Not including differences in piston tops, head gasket thicknesses and head chamber volume, all you need is a simple formula for a cylinder (pi * radius^2 * height), and multiply that by 8. Remember that the bore size is the diameter, and that a radius is one half of that measurement.
So, you would have:
pi * 2.015^2 * 2.87
~3.14 * ~4.06 * 2.87
or roughly 36.6
Now multiply that by 8, and you have about 292 cubic inches.
Now for cc's, just convert cubic inches to cubic centimeters.
It equals approximately 4785cc.
Good luck!
2007-08-28 16:01:36
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answer #4
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answered by Doug K 5
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Volume = Pie(3.141593) * radsq * bore* #cyls
the conversion to meteric is 2.54 cubed, or 2.54*2.54*2.54=16.387 * 289 =4735.86 cc or 4.74 liters
2007-08-28 16:46:24
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answer #5
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answered by ClassicMustang 7
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It's now a 426 ci Hemi
2007-08-28 15:41:55
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answer #6
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answered by Anonymous
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((bore/2)Squared*pie))xstrokex8
2007-08-28 15:42:00
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answer #7
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answered by teamepler@verizon.net 5
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