2007-08-28 01:17:57 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Botany
No. 267 can be expressed as 89*3.
A prime number by definition is one that cannot be expressed as a product of any two whole numbers except itself and one.
2007-08-28 01:25:03 · answer #1 · answered by Anonymous · 2⤊ 0⤋
3 times 89 is 267, so no.
A prime number is only divisible by itself and 1.
2007-08-28 01:27:02 · answer #2 · answered by Anonymous · 0⤊ 0⤋
no, 2 + 6 + 7 = 15
1 + 5 = 6
6 is evenly divisible by 3,
267 is not prime.
The divisibility test for 3 is to add the numbers down to a single digit. If the result is 3, 6, or 9, then the number is evenly divisible by 3.
2007-08-28 01:46:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
No...prime numbers only have two factors 1 and itself...267 can be divided 1, 3, 89, and 267...therefore making it composite
2007-08-28 01:26:14 · answer #4 · answered by D J 3 · 1⤊ 0⤋
A prime number is a number that can be divided by itself and 1 only.
267 can be divided by 3 so is not prime.
2007-08-28 03:47:23 · answer #5 · answered by Como 7 · 1⤊ 0⤋
No. The sum of its digits is 15, which is
a multiple of 3. So 267 is also a multiple of 3.
In fact 267 = 89*3.
2007-08-28 03:40:49 · answer #6 · answered by steiner1745 7 · 0⤊ 1⤋
no, because 267/3=89
2007-08-28 01:52:50 · answer #7 · answered by Anonymous · 0⤊ 0⤋
no, as it is divisble by 3 and 89. Prime numbers can be divisible by 1 and the number itself.
2007-08-28 01:35:00 · answer #8 · answered by libraboy28 2 · 0⤊ 0⤋
It can be divided by three to give you 89 so it is not a prime number.
2007-08-28 01:25:24 · answer #9 · answered by allwell 2 · 1⤊ 0⤋
No. It is divisible by at least 2 other numbers besides 1 and itself.
2007-08-28 01:25:04 · answer #10 · answered by Ralfcoder 7 · 0⤊ 0⤋