An unknown liquid is used in a manometer. The pressure difference being measured produces a height difference in the manometer tube of 4.02 m for the unknown liquid. Using a liquid mercury manometer the pressure the pressure difference is recorded as 753.2 mm.
Calculate the density of the unknown fluid in g/cm3.
What is the pressure difference in kPa?
what equations do i need to use?
2007-08-28 00:44:35 · 2 answers · asked by darth maul apprentice 1 in Science & Mathematics ➔ Engineering
first lets get those heights both in mm 4.02 meters = 4020 mm the second is given 753.2 mm that will give a ratio of rise which equals 4020/753.2=5.33 to one or by interpretation the unknown density of fluid 2 is 5.33 times as easy to push uphill(less dense) as mercury..... since mercury has a density of 13.6 g/mm^3 we can just divide by 5.33 to get the density of 2...so 13.6/5.33=2.55 g/mm^3 is the density of fluid two.......
one Kpa =7.500 mm of Hg so since we know what the mercury pressure is at 753.2 mm we just divide 753.2/7.5=100.426 Kpa and since pressure acts equally on all things its the same Kpa for the fluid 2...Good luck from the E...
2007-08-28 02:11:51 · answer #1 · answered by Edesigner 6 · 0⤊ 0⤋
I definitely feel "dense" about not being able to answer this! ;)
But, even if I could, other than supply the links, below,
I wouldn't help you do your homework! ;)
2007-08-28 08:57:17 · answer #2 · answered by skaizun 6 · 0⤊ 1⤋