Depends on if the long side is toward the side of the lot or the front of the lot.
2007-08-25 13:12:01
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answer #1
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answered by Stuart 7
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This is so easy you can figure it out in your head. The answerer above me misread it completely and overcomplicated it beyond belief.
If the lot is 88 feet square, less one building dimension of 14 feet leaves you with 74 feet, half of which is the distance between the other two sides and the lot line. From the 88 feet subtract the other building dimension which leaves you with 68 feet, half of which is the distance from the other two sides to the lot line.
You should be able to get this without even putting pencil to paper, and certainly without using a calculator.
So easy a caveman could do it.
(88-14)/2
(88-20)/2
2007-08-25 13:19:17
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answer #2
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answered by Anonymous
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14 x 20 building already takes up 280 sq ft in the middle, so your lot area must be > 280 sq ft, so it cannot be 88 sq ft, probably you mean 880 sq ft
880 = 40 x 22 or 44 x 20
I like 40 x 22 as the lot size.
so 20 x 14 building in a 40 x 22 lot
10 ft on each side, and 4 ft front and back.
2007-08-25 13:14:06
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answer #3
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answered by vlee1225 6
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You would have 34 feet on each end on the long 20 foot side and 37 feet on each side on the narrow 14 foot end. Your lot would be 7,744 square feet and the building 280 square feet, leaving 7,464 square feet of property.
2007-08-25 16:28:39
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answer #4
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answered by Anonymous
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The trick lies in "....88 ft.square" which means 88ft. x 88ft. "14x20" is inferred as 14ft x 20ft. So the answer is easily deduced.
2007-08-25 13:31:04
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answer #5
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answered by P Y 2
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