2007-08-24 17:09:51 · 8 answers · asked by nil 1 in Science & Mathematics ➔ Engineering
The winding of a transformer has little resistance. If an ideal voltage source were applied a very large current would result in the winding the voltage was applied to. The other winding would show no steady state voltage (although there would be a transient pulse on the secondary just after power was first applied to the primary).
There are applications for which a short duration DC pulse is applied to the primary of a transformer. Since the pulse is a transient, power can be coupled to the output of the transformer and as long as the duration of the pulse is short excessive current is avoided.
2007-08-24 19:14:00 · answer #1 · answered by Anonymous · 2⤊ 0⤋
A transformer works by coupling a magnetic field from one coil to another coil(s). As magnetic lines of force cut through a conductor you can induce a voltage in the conductor. Moving these lines of force can be done mechanically such as in a generator where a magnet is spun inside a coil.
You can also create motion in a magnetic field by changing its intensity(strenght) . So if you have a changing magnetic field strenght the magnetic lines of force will expand and contract with the stenght of the field. If these varying lines of force cut through a conductor you will also generate a voltage.
This is the principle of a transformer, you are electrically creating a moving magnetic fileld in close proximity to a coil thereby inducing a voltage in that coil. As long as the magnetic field is moving you are producing a voltage . stop the field motion and voltage production is stopped. (Even if the field is still present)
Consider a car ignition coil. It is operating on pulses of DC from the battery. The initial application of voltage causes a magnetic field to be created. As the field is created the expanding lines of force cut through the conductors of teh secondary winding an induct a voltage. The more turns on the secondary the greater the induced voltage. At some tme the filed reaches full strenght for the applied voltage and the field stops expanding and so does the induced voltage. Remove the DC and teh magnetic field collapses. As the field collapses voltage is again produces as the magnetic lies of force retract again cutting through the conductors in the secondary coil.
2007-08-25 12:30:18 · answer #2 · answered by MarkG 7 · 0⤊ 0⤋
you wouldn't get voltage on the other side of the transformer because a transformer is an AC device. But if u may b applied too much DC voltage on either side, u might burn up the windings.
2007-08-25 00:57:57 · answer #3 · answered by Thomas 3 · 0⤊ 1⤋
usually transformer is given D.C. supply while carrying out maintainance........the dc supply is used to heat up the windings after the transformer is washed.........ac supply is not given as it wud produce ac flux and hence voltage on the other side and the water may get electrified...producing a shock to the person .......else dc supply is not given to a transformer.....
2007-08-25 04:08:03 · answer #4 · answered by lion 1 · 0⤊ 1⤋
At best, it won't work. Usually it will burn up a fuse or the transformer and possibly the environment around the transformer. Transformers are AC devices.
2007-08-25 00:23:55 · answer #5 · answered by Anonymous · 0⤊ 1⤋
It does not work because it is ac device and it needs ac supply for producing flux and without flux the emf cannot be induced in the secondary therefore we don't get voltage at the secondary.
2007-08-25 01:37:26 · answer #6 · answered by arunr_8teen 1 · 0⤊ 0⤋
Anything from "hum and get hot" to "blow the whole neighborhood off the map," depending on how big an installation you are talking about.
2007-08-26 00:45:25 · answer #7 · answered by aviophage 7 · 0⤊ 0⤋
You create an inefficient electromagnet.
2007-08-25 04:08:24 · answer #8 · answered by Irv S 7 · 0⤊ 1⤋