energy conversion?

0 ⤊

a 200 v shunt motor develops 23 Hp, when taking 20.2kW. the field and armature resistance are 50 ohms and 0.06 ohms respectively. What is the efficiency when the output is 10 Hp?

with solution please..hhe..thank you =]

2007-08-23 01:29:22 · 2 answers · asked by aeiou 1 in Science & Mathematics ➔ Engineering

2 answers

Shunt winding power: 200^2 / 50 = 800 Watts

23 HP = 17.158 kW

20.2 kW - 800 Watt = 19.4 kW armature power

Efficiency of motor (armature)
17.158 / 19.4 = 88.44%

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10 HP = 7.46 kW

armature power = 7.46 kW / 0.8844 = 8.435 kW
total power = 8.435 kW + 0.8 kW = 9.235 kW

efficiency = 7.46 kW / 9.235 kW = 80.7%

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2007-08-23 04:29:49 · answer #1 · answered by tlbs101 7 · 0⤊ 0⤋

.792736453542

2007-08-23 10:52:18 · answer #2 · answered by mike 5 · 0⤊ 0⤋