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Regular black holes are the ones that have a dead end.
Two-way wormholes are black holes that serve as entry points to each other that resembles a portal.

2007-08-22 23:19:10 · 2 answers · asked by daniel_anzaldo 1 in Science & Mathematics Astronomy & Space

2 answers

If a black hole could exist there would be a singularity at the center,a point of no dimensions.
A worm hole connected to a remote point in space implies that space in some way would be folded to bring the worm hole in contact with another point in space.
The universe expands spherically so any two points in space are always separated from each other making it impossible for a worm hole to be a portal.

2007-08-22 23:58:16 · answer #1 · answered by Billy Butthead 7 · 0 0

Pretty dad gummed slim

to

almost zero.

Remember black holes and worm holes are invisible. So you can't just go out looking for them with binoculars or a telescope. Also, if you envision a black hole in your mind...
How will you ever determine that you have moved around to
the back side of it to see if it has a matching construction on the other side, or just stops. Is a black hole just sitting there motionless for you to move around and observe it? Can you even get near one to make observations without being sucked inside? Is this actually a matter of pondering the unknown? And the benefit of forcing this issue to a head is what?

Given that you have explained to us what a two-way wormhole is, will you please produce your text reference which defines one as such, and the particular space object "name" or "catalog number" which has been identified as one.

Thank-you,
Zah

2007-08-23 00:40:34 · answer #2 · answered by zahbudar 6 · 0 0

Pretty much zero, since worm holes are not known to exist outside the realm of science fiction. They were invented by science fiction writers to circumvent the limitations of light speed. Black holes, on the other hand, are a well-known phenomenon, their existence proved beyond a doubt both theoretically and observationally.

2007-08-23 01:35:27 · answer #3 · answered by GeoffG 7 · 1 0

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