if you can please can you explain with formulas etc how this is possible? thankss
2007-08-22 22:58:55 · 7 answers · asked by sweetmango 2 in Science & Mathematics ➔ Mathematics
Hi,
Yes, you can use the Law of Cosines. If a, b, and c are the sides of the triangle opposite angles A, B, and C respectively, then the formulas you can use are:
c² = a² + b² -2ab*cos C
a² = b² + c² -2bc*cos A
b² = a² + c² -2ac*cos B
That way if you knew a, b, and c, you could find the cosine of the desired angle. When you take the cos^-1 of that value, it will give you the angle's measurement.
I hope that helps!! :-)
2007-08-22 23:07:11 · answer #1 · answered by Pi R Squared 7 · 0⤊ 0⤋
ya , like they said.
but for future use, if you have a similar question where you got a number of facts about a triangle and ur not sure if the rest can be found from it, ask you self.. how many triangles can i have from these given facts?? if more than one, then no, but if its just one, then yes.
in your case, u have 3 sides, and u can only have ONE triangle shape with a given 3 -sides, which is why there is the triangle congruency theorem SSS
2007-08-23 00:04:08 · answer #2 · answered by Yazan 2 · 0⤊ 0⤋
yes it's possible.
http://www.teacherschoice.com.au/Maths_Library/Trigonometry/solve_trig_SSS.htm
you need the cosine rule to solve the angles of a triangle if you only have the 3 side lengths, the sine rule can solve just about any other combination of knowns.
check out that website :).
2007-08-22 23:09:46 · answer #3 · answered by Jeff 1 · 0⤊ 0⤋
yes.u draw a line from one angle to the base line thus dividing the line into 2 and the angle into 2.then use cosine,sine and tan calculate the angles.that is what i would do.
2007-08-22 23:31:36 · answer #4 · answered by rukie 2 · 0⤊ 0⤋
Use the Law of Cosines.
c² = a² + b² - 2ab cosC
2ab cosC = a² + b² - c²
cosC = (a² + b² - c²) / (2ab)
C = arccos[(a² + b² - c²) / (2ab)]
Do the same for the second angle. The third angle is 180° less the sum of the first two.
2007-08-22 23:04:06 · answer #5 · answered by Northstar 7 · 1⤊ 0⤋
you can calculate by using
a^2=b^2+c^2-2ac cosB
2ac cosB=a^2+c^2-b^2
cosB=a^2+c^2-b^2/2ac
B=cos^-1 a^2+c^2-b^2/2ac
apply this to get the other angles i mean the same step
2007-08-22 23:36:24 · answer #6 · answered by prinsex prex 2 · 0⤊ 0⤋
Yes, it is possible.
You can apply trigo function relations.
2007-08-22 23:10:42 · answer #7 · answered by Elmer B 2 · 0⤊ 0⤋