4x^3-16x^2-9x+36
2007-08-22 18:11:18 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
4x² (x - 4) - 9 (x - 4)
(x - 4) (4x² - 9)
(x - 4) (2x - 3) (2x + 3)
2007-08-22 20:03:47 · answer #1 · answered by Como 7 · 1⤊ 0⤋
4x^3 - 16x^2 - 9x +36
= 4x^2(x -4) - 9 (x -4)
= (4x^2 - 9)(x - 4)
=(2x + 3)(2x - 3 )(x - 4)
2007-08-23 01:22:00 · answer #2 · answered by Snoopy 3 · 0⤊ 0⤋
GROUPING is the appropriate method of factoring in your polynomial expression..
(4x^3-16x^2) - (9x-36)
by common monomial factoring...
4x^2(x-4)-9(x-4)
regroup...
=(x-4)(4x^2-9)
the prime factors of your expression will be...
=(x-4)(2x+3)(2x-3)
hope it helps...
2007-08-23 01:44:04 · answer #3 · answered by >bLueeyes< 2 · 0⤊ 1⤋
4x^3 - 16x^2 - 9x + 36
4x^2(x-4) - 9(x-4)
(4x^2-9)(x-4)
(2x-3)(2x+3)(x-4)
2007-08-23 01:15:25 · answer #4 · answered by UnknownD 6 · 0⤊ 0⤋
4x^2(x-4)-9(x-4)
=(x-4)(4x^2-9)
=(x-4)(2x+3)(2x-3)
2007-08-23 01:16:23 · answer #5 · answered by Jahir 2 · 0⤊ 0⤋
kinda rusty on this but use quadratic square, quadratic equation, or divide it by a like term
2007-08-23 01:18:21 · answer #6 · answered by sunnyd 3 · 0⤊ 0⤋
(2x+3)(2x-3)(x-4)
100% sure... :)
2007-08-23 01:22:17 · answer #7 · answered by William99929 2 · 0⤊ 0⤋