Arrange the following in expected order of solubility in water from lowest to highest: I2, KI, and C8H8? Could someone explain it to me plz???
2007-08-22 15:44:44 · 4 answers · asked by Dom Dom Damdum 3 in Science & Mathematics ➔ Chemistry
Partial answer. C8H8 is water-hating (hydrophobic), so it wil be the least solubile. It will not mix. Their atoms are covalently bonded and the molecule sticks together and dislikes water when entering. The others are ionic bonds and will dissolve into ions with water separating the individual ions. The strengths of the ions will let you know which ones are more soluble. Id guess I2 least off the top of my head, but you need to check...
2007-08-22 16:05:07 · answer #1 · answered by BJ 4 · 1⤊ 0⤋
sorry i can't help u with ur quesion but i want to learn so if u have time can u tell me what this is (I2, KI, and C8H8) i mean after u find out what it is first.....hehe...
emai - pen.rock@hotmail.com
thnx
2007-08-22 15:51:42 · answer #2 · answered by freelance812 2 · 0⤊ 0⤋
It is based on polarity.
KI is ionic and easily dissolves.
C8H8 is hardly polar, but should be a bit more soluble than I2 which has no polarity at all.
2007-08-22 15:51:18 · answer #3 · answered by reb1240 7 · 1⤊ 0⤋
I think it's B C A. Lucky guess.
2007-08-22 15:48:55 · answer #4 · answered by Anonymous · 0⤊ 0⤋