how do i solve this?

Question

please post helpful steps. i need to learn this, thanks soooo much!!!!


7(5x+3)=7(x+5)-14+28x

Answer 1

7(5x+3)=7(x+5)-14+28x You want to find X

Let's simplify.

35x+21=(7x+35)-14+28

All parts are multiples of 7. Let's divide each by 7.

5x+3=(x+5)-14+28

subtract 3 from each side and simplify the -14+28

5x=(x+5)+11

simplify

5x=x+5+11=x+16

now we know that

5x=x+16

subtract x from each side

4x=16

divide both by 4

x=4

Now, we know that
7(5x+3)=7(x+5)-14+28x and x=4

Answer 2

7(5x+3)=7(x+5)-14+28x

First, let's simplify:
7*5x + 7*3 = 7*x + 7*5 - 14 + 28x
Multiply:
35x + 21 = 7x + 35 - 14 + 28x
Now lets add the x variables and the integers:
35x + 21 = 35x + 21
Both sides of the equation are the same and, therefore, x may equal any number.

Answer 3

Distribute the 7's
35x + 21 = 7x + 35 - 14 + 28x
Combine like terms
35x + 21 = 35x + 21
Since you have the same expression on both sides of the equations, the solution is all real numbers. This means that you can place any number in for x and the equation will be true.

Answer 4

Given: 7(5x+3)=7(x+5)-14+28x

Multiplying terms gives:
35x + 21=7x+35-14+28x

Adding/subtracting similar terms only on right side of = mark gives:
35x +21=35x + 21


Look at the equation above careful. 35x and +21 both appear on the left and right side of the equal (=) mark. If we simplify it further, we will eventually end with zero equals zero (0=0). We do not need to simplify further because the equation is obviously equal on both sides of the equal (=) mark. You did not state in the problem above what you meant by "solve". The only solution that came to mind was to prove the equality by simiplification.

Answer 5

Sure, but pay attention. Put down that book and turn off the tv.

first clear all the parentheses as follows:


35x +21= 7x+35-14+28x

combine like terms

and you get

35x+21=35x+21 or 21=21...which is true.

hmmm.

something a little screwy here.

basically, the solution is that your original equation is true for all values of x, since x falls out of the equation when you simplify.

Answer 6

7(5x+3)=7(x+5)-14+28x

first distribute-

35x+21=7x+35-14+28x

combine like terms-

35x+21=35x+21

the two equations are equal

therefore it is an infininate amount of answers.

Answer 7

first multiply then add or subtract

35x + 21 = 7x + 35 - 14 + 28x
combine like terms
35x - 7x - 28x = 35 - 14 - 21
x = 0

Answer 8

this is distributive property, so u multiply the number outside of the parentheses by both of the numbers inside of the parentheses first:
35x+21=7x+35-14+28x
Then, u add like terms on either side:
35x+21=35x+21
Then, u substitue 1 for x and both sides are equal:
35+21=35+21

Answer 9

I would factor out 7 thus 7(5x+3)=7(x+5)-7(2+4x)
so 5x+3=x+5-(2+4x)
then 5x+3=x+5-2-4x
isolate the x on one side:

8x=0. x=0 check it :-)

Answer 10

35x+21=7x+35-14+28x
35x+21=35x+21