construct triangle ABC with vertices A(-4,2), B(4,3), C(1,-3). list the angles in?

Question

Please help

Answer 1

To work out an angle construct the two vectors to that angle and take the dot product.

AB = = <4+4, 3-2> = <8, 1>
AC = = <1+4, -3-2> = <5, -5>

|| AB || = √(8² + 1²) = √(64 + 1) = √65
|| AC || = √[5² + (-5)²] = √(25 + 25) = √50 = 5√2

AB • AC = <8, 1> • <5, -5> = 40 - 5 = 35

Angle A can be expressed in terms of the dot product as:

cosA = (AB • AC) / {|| AB || || AC || = 35 / [(√65)(5√2)]
cosA = 7 / [(√65)(√2)] = 7 / √130

A = arccos(7 / √130 ) ≈ 52.1°

The other angles are similarly calculated.

Answer 2

I'm assuming you want to know angles CAB, ABC, and BCA.
It's an Isocoles triangle, so base angles(CAB,ABC) are equal.

CAB and ABC- 52 Degrees
BCA- 76 Degrees