Identify the value of the discriminant for the equation 6x2 = 2x – 1.
(A) 28
(B) 24
(C)–22
(d) –20
Which one?
2007-08-22 13:14:41 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If an equation is in the form ax² + bx + c = 0, then the discriminant is b² - 4ac.
You have 6x² = 2x - 1. Adding -2x + 1 (to set the quadratic equal to zero),
6x² - 2x + 1 = 0.
The discriminant is b² - 4ac
= (-2)² - 4(6)(1)
= 4 - 24
= -20
2007-08-22 13:20:58 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The discriminant is b^2-4ac
6x^2-2x+1=0
(-2)^2-4(6)(1)=-20
--
(d) -20.
2007-08-22 20:21:46 · answer #2 · answered by de4th 4 · 0⤊ 0⤋
I assume you mean
6x² = 2x - 1
6x² - 2x + 1 = 0
The discriminant is:
b² - 4ac = (-2)² - 4*6*1 = 4 - 24 = -20
The answer is (d).
______________
2007-08-22 20:18:29 · answer #3 · answered by Northstar 7 · 0⤊ 0⤋