please help
2007-08-22 12:40:27 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1 and 117! 3 & 39
WOOT do I get 10 points :)
my answer is bestededed because I am the cutest
2007-08-22 12:43:01 · answer #1 · answered by Monique S 3 · 0⤊ 2⤋
The prime factorization of 117 is:
3^2 * 13^1.
Therefore, here are all the ways to get 117 by multiplying positive integers (leaving out the 1's from the products which already have two or more numbers, and you can always change the order the numbers are being multiplied in, of course):
3 * 3 * 13
9 * 13
3 * 39
1 * 117
2007-08-22 12:46:22 · answer #2 · answered by darthsherwin 3 · 0⤊ 0⤋
3 x 3 x 13 = 117
2007-08-22 12:43:48 · answer #3 · answered by John V 6 · 0⤊ 0⤋
Notice that the digits of 117 add up to 9.
So 9 is a factor of 117 and so is 3.
So we can have 117 = 3*39 = 9*13 = 3*3*13.
2007-08-22 13:08:54 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
9 x 13 = 117
3 x 39 = 117
1 x 117 = 117
I think that's it..
2007-08-22 12:47:04 · answer #5 · answered by alexk 2 · 0⤊ 0⤋
sum of digits in 117 = 1 + 1 +7 =9
so it is divisible by 3
117 = 3(39)
again 39 is divisible by 3 , because (3 +9) =12 is divisible by 3
117 =(3)(3)(13)
2007-08-22 12:48:56 · answer #6 · answered by mohanrao d 7 · 0⤊ 0⤋
1*117 9*13
2015-09-15 12:01:17 · answer #7 · answered by neydi 1 · 0⤊ 0⤋
1 time 117 or 117 times 1
2007-08-22 12:44:06 · answer #8 · answered by xfileaddict1969 2 · 0⤊ 2⤋
1 times 117??
2007-08-22 12:42:53 · answer #9 · answered by khannh1995 3 · 0⤊ 2⤋
3*3*13
2007-08-22 12:43:34 · answer #10 · answered by ironduke8159 7 · 0⤊ 0⤋