what volume is occupied by 2.5g of O2 gas at 25C and at 600mm/hg of pressure?

Answer 1

Using the ideal gas law, V = NRT/P

First you convert grams to moles. 2.5 g O2 = 7.8 x 10^-2 moles.

Now convert your temperature to Kelvin. 25*C = 298 K

Since the ideal gas constant is expressed in atmospheres, you'll need to convert that as well. 600 mm Hg = .80 atm

Ideal gas constant = .08206 L atm/mol K

So, your equation should look like this:

V = (7.8 x 10^-2 mol)(.08206 L atm/mol K)(298 K) / .80 atm

Since moles, atmospheres, and kelvin cancel each other out, you're left with an answer in liters. V = 2.4 L

Answer 2

V = nRT/p

(2.5/32) x 8.31 x 298 x (760/600)

This answer will be in cubic metres.

Answer 3

pv=nrt
pressure x volume = constitent x moles of gas x temp

Answer 4

2.24 liters