how do you solve x^2 - 9 and the equation x^2 - 10
2007-08-22 11:06:30 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^2 - 9 is the difference of 2 squares and is factorable to:
(x+3)(x-3)
the second expression you gave is not an EQUATION because x^2 - 10 does not equal something. All equations are equal to something. If you mean this x^2 - 10 is equal to zero then:
x^2 - 10 = 0
x^2 = 10
x = +/- SQRT (10)
If you just want to factor the expression then:
(x-radical10)(x+radical10)
2007-08-22 11:17:35 · answer #1 · answered by 037 G 6 · 0⤊ 0⤋
The second equation does have a solution... it's just not in integers or rational numbers.
The 2nd equation can be factored as
(x+sqrt(10))(x-sqrt(10)), where "sqrt(10)" means square root of 10.
2007-08-22 11:16:59 · answer #2 · answered by Yokki 4 · 0⤊ 1⤋
i'm assuming the two is meant to be an exponent. 5y² - 80 = 0 component out 5. 5(y² - sixteen) = 0 y² - sixteen is the kind of two squares. y² - sixteen = (y)² - (4)² keep in mind that a² - b² = (a - b)(a + b). 5(y² - sixteen) = 0.5(y - 4)(y + 4) = 0 sparkling up. y - 4 = 0 y = 4 y + 4 = 0 y = -4 answer: y = ± 4
2016-12-16 03:20:45 · answer #3 · answered by messenger 4 · 0⤊ 0⤋
To be more exact the first solution is x = +/- 3 and the second solution is x=sqrt of 10
2007-08-22 11:51:04 · answer #4 · answered by SpinDeflector 1 · 0⤊ 1⤋
the answer to the first one is (x+3)(x-3)
the second one doesn't have an answer because 10 isn't a perfect square and it lacks a middle term.
2007-08-22 11:11:48 · answer #5 · answered by peteryoung144 6 · 0⤊ 1⤋
x^2 - 9 = (x + 3) (x - 3)
x^2 - 10 = (x + Sq Rt 10) (x - Sq Rt 10)
2007-08-22 11:15:16 · answer #6 · answered by robertonereo 4 · 0⤊ 1⤋