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7 answers

π + x + e = ±(π + √2 + e)
x = √2 or x = -√2 -2(π + e)

2007-08-22 09:03:20 · answer #1 · answered by sahsjing 7 · 2 1

Hey there!

We can find the first answer. Note that the two equations are exactly equal to each other. Since they are equal, i.e. π=π, x=sqrt(2) and e=e.

So x=sqrt(2).

However, the answer can be proved by using the quadratic formula.

Using the quadratic formula, you get two solutions, x=sqrt(2) and x=-sqrt(2)-e-π.

Hope it helps!

2007-08-22 18:51:18 · answer #2 · answered by ? 6 · 0 0

x = √2 or -√2 - 2π - 2e

You can see that the left side matches the right side exactly, except that x is replaced by √2. This means that x = √2 must be a solution. x = -√2 - 2π - 2e is also a solution because it would make the left side equal to (-π - √2 - e)^2, which has the same value as (π + √2 + e)^2 since (-1)^2 = 1.

2007-08-22 16:02:06 · answer #3 · answered by DavidK93 7 · 0 2

First off, x just replaces the square root of two

So you can ignore the left half of the equation, since you already know that x = the square root of two

Now, pi approximates to 3.1415926 (count the letters in "how I need a drink, alcoholic of course"), e is about 2.71828183, and the square root of two is about 1.41421356. Add them all together, and you get 7.27408799 , and square it, and you get about 52.91

2007-08-22 16:14:08 · answer #4 · answered by Just Jess 7 · 0 0

(π + x + e)² = (π + √2 + e)²?

39

2007-08-22 16:01:52 · answer #5 · answered by god knows and sees else Yahoo 6 · 1 3

Shoe polish

2007-08-22 16:04:47 · answer #6 · answered by Sean Thornton 1 · 1 3

Could this be homework??

2007-08-22 16:08:31 · answer #7 · answered by ladyfirefighterfd13 3 · 0 1

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