Again!!! 5x^3 - 5x +1 divide by x-3 ?

Question

Thank you for the answers before, but I don't know the way how to get to the solution.

Answer 1

Use synthetic division:
3|5 0 -5 1
. .. 15 45 120
---------------
...5 15 40 |121
Therefore, the answer is
5x^2+15x+40 + 121/(x-3)

Answer 2

Set it up like long division with x-3 outside and 5x^3 + 0x^2 -5x +1 inside

x goes into 5x^3 , 5x^2 times so put that on top and multiply by x-3, then subtrtact. You get 15x^2.

x goes into 15x^2, 15x times, so multiply it be x-3 and subtract. You get 40x

x goes into 40x, 40 times, so multiply it be x-3 and subtract. You get 121

Your answer is 5x^2 +15x +4 0+ 121/ (x-3)

Hope this helped.

Answer 3

if its posite and negavitve then 5*(+1)/(-3)= 5 time postie 1 = postie five . takes 5*(+1) and then take the *-3 and make it (-3) then divide postie 5 and divide it by negavtive 3 and its postive 15 or negavtive 15 cannt remember

Answer 4

x - 3 ) 5x^3 + 0x^2 - 5x + 1 ( ans: 5x^2 - 15x - 50
-5x^3 - 15x^2
____________
0 - 15x^2 - 5x
15x^2 -45x
____________
- 50x +1
50x -150
__________
-149 (Remainder)

Answer 5

write it out like regular long division
what times x equals 5x^3(5x^2)
times x-3 by that and put it under big thing (dont know wats callerd)
subtract
and keep going with wat i startd w/

google long division help -c wat u get