How would I find sin AND cosine of this trangle??

Question

angle 30 degrees
opposite: X
Hyptonus: 6
Ajacent: Y

Answer 1

You could look them up in a table in a book. You could get them from a calculator that has trig functions.

Or you could calculate the lengths of the other two sides of the triangle and get the sine/cosine from the ratios of the lengths of the sides. (Of course to get the lengths of the other two sides you'd need either the sine or cosine of 30 degrees.)

Answer 2

first are x and y the sides or angle

if sides then your mentioning a right angle triangle

i cant draw a figure here but anyway hypotenuse is 6, angle is 30 opposite side is x and its adjacent side is y ok

so 2 methods 1. theres a formula its better if u know it at young age in a right angle triangle 30:60:90 angles then sides 1:square root(3):2 i.e like x : root 3 x: 2x

so one side hypotenuse is 2x =6 longest side x = 3
rem sides 3 shortest side the one facing 30 degrees and 3 root 3 is one facing 60 degrees the next longest side

x=3 , y = 3 x 1.732 ( root 3 = 1.732) = 5.1

theres another method you know the angles 30,60 90 ,hypotenuse is 6

sin 30= (1/2) = opp side/hypotenuse(6) . so opp side = 6 x 1/2 = 3

adjacent side = cos 60 = adjacent side/ hypotenuse . sp adj sid = 6 x root3/2 = 3 root 3 = 5. somethin

did u understand

always remember hypotenuse refers to a rt triangle

Answer 3

All you need to know is the angle.

sin(30) = 0.5
cos(30) = sqrt(3)/2 or about 0.866

Additionally:
X = 6*sin(30)
Y = 6*cos(30)

Answer 4

sin of this triangle is x/under root of x square and y square
cosine of this triangle is y/under root of x square and y square