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What is the vertical asymptote of the curve

y=(-1x^3)/x-10

2007-08-22 06:24:51 · 2 answers · asked by Mark M 1 in Science & Mathematics Mathematics

2 answers

The asymptote occurs at x=10, because the denominator then equals zero, which causes y(x) to blow up to infinity.

2007-08-22 06:29:24 · answer #1 · answered by Not Eddie Money 3 · 0 0

If your function is y = (-x^3)/(x - 10), then Not Eddie is correct.

But if your function is (-x^3)/x - 10, then the function does not have 0 in the domain, and since x is never 0, you can simplify the function to y = -x^2 - 10, which has no vertical asymptotes.

2007-08-22 15:53:42 · answer #2 · answered by Tony 7 · 0 0

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