when i did it my answer was
3(4x+11)/(x+3)(x+2)
but that does seem right..
is it?
2007-08-22 05:38:21 · 7 answers · asked by Mercedes 1 in Science & Mathematics ➔ Mathematics
You're right
2007-08-22 05:46:00 · answer #1 · answered by chasrmck 6 · 0⤊ 0⤋
you are right
9(x^2 + 5x + 6) + 12/(x +3)=
9/(x +3)(x + 2) + 12/(x +3)=
9/(x + 3) (x + 2) + 12 (x + 2)/(x + 3) (x + 2)=
9 + 12x 24/(x + 3)(x + 2) =
12 x + 33/(x + 3)(x + 2) =
3(4 x + 11)/(x + 3(x + 2)
2007-08-22 12:53:48 · answer #2 · answered by mohanrao d 7 · 0⤊ 0⤋
i think you have to factoris it.
x^2+5x+6 can be changed into (x+3)(x+2)
and then some how add or cancel out the x+3 on the denominator of the other fraction.
that all i can do, i havnt been to school since june haha
2007-08-22 12:47:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I got the same thing.
[9/(x^2+5x+6)]+12/(x+3)
9/[(x+2)(x+3)] + [12(x+2)/[(x+2)(x+3)]]
(12x+24+9)/[(x+2)(x+3)]
(12x+33)/[(x+2)(x+3)]
3(4x+11)/[(x+2)(x+3)]
2007-08-22 12:50:20 · answer #4 · answered by BlueWolf 1 · 0⤊ 0⤋
(9/x^2+5x+6)+12/(x+3)<-- I assumed you meant this
= 9/[(x+2)(x+3)] +12/(x+3)
= 9/[(x+2)(x+3)] +12(x+2)/[(x+2)(x+3)]
= [9+12(x+2)]/[(x+2)(x+3)]
= (12x+18)/[(x+2)(x+3)]
= 6(x+3)/[(x+2)(x+3)]
= 6/(x+2)
2007-08-22 12:52:34 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
Yeppers!
2007-08-22 12:47:10 · answer #6 · answered by gebobs 6 · 0⤊ 0⤋
Your answer is correct
2007-08-22 12:46:03 · answer #7 · answered by Anonymous · 0⤊ 0⤋