true or false?
To be able for the rocket to launch, the thrust must be equal to the gravitational force.
2007-08-22 00:56:36 · 7 answers · asked by Arvelyn A 1 in Science & Mathematics ➔ Physics
False , it should be greater
2007-08-22 01:46:09 · answer #1 · answered by dy/dx 3 · 1⤊ 0⤋
Gravitational force is the weakest force in the universe. It araises due to the mass of the bodies. We speak gravitational pull when we have two masses(just remember there is also an evidence for negative gravity). Your question is very straight forward. But the rocket launching includes large number of consideration. For example, the opposite force of air and the rotation of earth, etc.
Rocket is working under the newtons third law and the conservation of linear momentum.
Considering the earth is not moving and spining and there is no air, your question can be answered easily. I hope that you imagined like that situation. If the thrust given by the rocket is equal to the gravitation pull, then it will come down because of the reason rocket also attract the earth but it is negligible in amount. So Rocket will go away only when it give that thrust greater than the gravitational pull. It is very basic and easy calculation.
2007-08-22 09:55:54 · answer #2 · answered by thiru 1 · 0⤊ 1⤋
If the thrust was equal to the the weight of the rocket(gravitational force) The rocket would just remain suspended but going nowhere.
The rocket in order to be launched into Space must have enough power to generate a force(thrust) that would move at or faster than the escape velocity.
That means that the Inertial Power generated by the Rocket must exceed the Power of Gravity at the surface of the earth.
2007-08-22 08:36:42 · answer #3 · answered by goring 6 · 0⤊ 0⤋
the force that's holding the rocket down is it's weight, say 1,000,000 lbs. then for the rocket to launch, the thrust has to be more than the 1,000,000 lbs holding it down. so if the thrust was 1,000,001 lbs, the rocket would accelerate upward but very slowly. it's obvious that the greater the thrust force than the weight force, the faster the rocket will launch.
2007-08-22 08:52:21 · answer #4 · answered by ftm821 2 · 0⤊ 0⤋
The threshold velocity by which a carrier gets launched is
called Escape velocity. Escape velocity varies from planet
to planet.
Going by the law of conservation of energy
At the edge of the surface of the earth
mgh = .05 m v * v /2
v = sqrt(2 * g * h/m)
This varies between planets. Not only a rocket , but even
a stone which is thrown at that speed escapes the earth's
gravitational force of attraction.
This speed is approximately equal to 11.7 km/s
2007-08-22 08:17:48 · answer #5 · answered by Gopal 2 · 0⤊ 1⤋
False -- it must be greater.
2007-08-22 08:05:10 · answer #6 · answered by Nature Boy 6 · 1⤊ 0⤋
false.
It must be greater.
2007-08-22 08:04:47 · answer #7 · answered by Anonymous · 2⤊ 0⤋