Explain atomic bombs? How do they produce such mass destruction etc,...?

Answer 1

The easiest way to explain it is E=MC*C

E equals your energy output

M equals the amount of matter you start with in the equation

C equals the speed of light or 300000000 meters per second

The Second C is the speed of light but represents acceleration( You mulitiply by itself)

So Energy = Mass times 90000000000000000 meters /second/second

So a very small amount of mass can make a very large amount of energy.

Answer 2

The subatomic particles of the nucleus have masses that vary from element to element and reflect the energy tied up in holding the nucleus together. Look at the periodic table of the elements, and notice, for example, that Hydrogen actually has an atomic mass of slightly greater than 1.0000. Part of that difference is due to the other isotopes, which are heavier, but even pure protium has an atomic mass greater than one. Helium, too, has an atomic mass greater than 4.

Uranium 235 has an atomic mass that is also greater than 235. However, the great bulk of elements in between the light elements and the heavy elements have masses that are less, per particle, than those at the ends of the mass curve.

When Uranium 235 splits into its products, those products have less mass per nucleon than the U-235 had. The "missing" mass is converted into energy following the well-known Einstein equation, E = mc^2.

Mechanically, Uranium bombs and plutonium bombs are dramatically different. U-235 makes a nuclear explosion you assemble a supercritical mass of the material. From time to time, a U235 nucleus emits a neutron, as part of a cascade process that causes the uranium to decay into thorium 233 (which is also fissionable, btw). If the neutron hits a U-235 nucleus, the nucleus will fission into krypton, argon, and between two and five neutrons. Each of those neutrons can split another atom. Now in order to make sure you have a boom instead of a fizzle, an A-bomb uses an initiator. This is a mass of polonium, which emits alpha particles, surrounded by aluminum foil, which in turn is surrounded by beryllium powder. The chemical explosive that creates the critical mass (i.e., enough fissionable material that the material will set off a chain reaction) rips the aluminum foil, enabling the alphas from the polonium to hit the beryllium, resulting in a FLOOD of neutrons. The chain reaction ramps up to a nuclear explosion in about 8 milliseconds, and the bomb blows itself apart. Actually, only about 0.5% of the U-235 is fissioned. Uranium is so reliable that Little Boy, the bomb we dropped on Hiroshima, was not tested before being employed.

Plutonium is different, because it ramps up more slowly, and because a neutron from cosmic radiation can start the reaction before the mass is truly critical. The result is a fizzle. SO the geometry of a plutonium bomb is much more complex, relying on explosive lensing and finely-divided material to produce the critical mass through overpressure. Because of the extreme complexity of plutonium bombs, the decision was made to test the weapon. Whither Trinity and Alamogordo.

The resulting energy defect is emitted in the form of high-speed products (which impart kinetic energy to their targets) and high-energy photons (gamma rays).

Answer 3

in the simplest of terms, its wind damage plus heat damage. The wind we see every day is cool air vs warmer air. When a nuclear explosion occurs, the center is superhot and the air expands outward to about 800 mph and because it expands so quickly a vacuum in the center is created. The hot air rushes out then the vacuum sucks it back to the center. Watch any film clips you can of tests during the 50's, then there is the heat from the fission explosion, it doesn't travel as fast, and can be dissipated by sturdier buildings (brick, concrete block, etc) But most destruction outside of ground zero is from the wind created. This is a very simple explanation

Answer 4

its the splitting the big nuclei of the uranium. this produces the energy -the energy is "stored" in the nucleus of the uranium atom. However the nucleus itself is very unstable and a single neutron hit would split it in two. unlike chopping the wood, the split nuclei are containing much less energy now, the rest being radiated as heat and new hi-speed neutrons to split another nuclei. there are stable elements -the row is ending with lead, which is the final result of uranium splitting and a perfect deflector/absorber of neutrons. these stable elements need the lowest energy to keep their nuclei in shape and are thus least vulnerable to the splitting /big atoms/ or fussion /small atoms, like hydrogen etc./

the complete theory behind this is a rather complicated to write here.

Answer 5

A-Bomb:forcing fissionable materiel into a critical mass and achieving an uncontrolled nuclear reaction.
H-Bomb(fusion bomb) Same thing different type of materiel.A fussion bomb uses a small A-Bomb as the initiator.The result is a fusion reaction.Higher yield,worse radiation.

Answer 6

much of the energy, when mass is converted to energy in a bomb is converted to heat. Instantaneous heating of the air surrounding the device to several tens of thousands of degrees causes the air to expand rapidly at Mach speed. (Classic spherical shock wave). As the superheated column of air cools it begins to flatten out giving the classic mushroom cloud. In reality nothing more than the transfer of a tremendous amount of heat energy.

Answer 7

It's the practical application of e=mc2;

The bombardment of highly enriched uranium or plutonium isotopes by neutrons discharges the energy. U-235 isotope fissions or splits, producing heat in a continuous process (AKA: chain reaction).

The amount of mass destruction would depend on air burst or ground detonation, terrain, urban density, ground type, weather conditions, and so on, the effects of any detonation include

Primary shockwave
Thermal Radiation Effects
Direct Nuclear Radiation Effects
Radioactive Fallout
Electromagnetic Pulse

Blast Wave overpressure of a 100 meg detonation the size of Tzarrina megabomb:
30 psi: 5.64 miles
10 psi: 10.35 miles
4 psi: 18.13 miles
2 psi: 26.71 miles
0.5 psi: 68.52 miles
0.2 psi: 140.36 miles

Key to the Damage:
15 psi Complete destruction of reinforced concrete structures, such as skyscrapers, will occur within this ring. Between 7 psi and 15 psi, there will be severe to total damage to these types of structures.
5 psi Complete destruction of ordinary houses, and moderate to severe damage to reinforced concrete structures, will occur within this ring.
2 psi Severe damage to ordinary houses, and light to moderate damage to reinforced concrete structures, will occur within this ring.
1 psi Light damage to all structures, and light to moderate damage to ordinary houses, will occur within this ring.
0.25 psi Most glass surfaces, such as windows, will shatter within this ring, some with enough force to cause injury.

I didn't calc. thermal radiation effects, fallout or EMP damage, but suffice it to say, i'd predict global impact winter....

Answer 8

It is like really easy to explain so I will leave it to the experts. See link

Answer 9

nuclear fission. http://en.wikipedia.org/wiki/Nuclear_fission