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I have some problem about how to calculate power for my system. i use water jet as prime mover to move the turbine. Here i give the spec of my system :-

Water Jet spec
1. Operation pressure = 40 bar
2. Suction Volume = 17litre/minutes

We know that to calculate power is equal H(head) x flow rate x g x Efficiency...But for my system i don,t know the best way to calculate power. If i used this spec to calculate power, the result that i get is to small. So hope you can help me to simplify this problem. Thank you.

2007-08-20 02:46:39 · 2 answers · asked by yie 1 in Science & Mathematics Engineering

2 answers

Hydraulic HP = GPM x lb/gal x H x Specific Gravity/33,000

17 liters/min = 4.49 GPM = GPM
Lb per gallon for water = 8.33
40 bar = 580.15 psi = 1339 feet of liquid head = H
Specific Gravity = 1.0 for water

Hydraulic HP = 4.49 GPM x 8.33lb per gal x 1339 ft of liquid head x 1.0/33,000

Hydraulic HP = 1.52

BHP = Hydraulic HP/Eff.

2007-08-20 17:06:22 · answer #1 · answered by gatorbait 7 · 0 0

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2007-08-20 09:54:55 · answer #2 · answered by KeepItReal 3 · 0 4

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