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3 answers

Copper has many different densities based on the alloy type, so this is kind of hard to answer. Pure copper (although I doubt this is what they are actually using in a rod) is 8.96 g/cm^3. So if this is a solid cylindric rod, the volume would be pi*(.4 cm)^2 * (100 cm) = 50.2 cm^3 * 8.96 g/cm^3 = 450 grams

But, like I said, they probably do not use pure copper in a rod. It depends on the alloy density.

2007-08-20 02:33:13 · answer #1 · answered by Jon G 4 · 1 0

I assume you mean the rod is cylindrical with a diameter of 80 mm. That's d = 0.08 m, and the cross-sectional area is A = pi*(d^2)/4. For volume, calculate V = A*L, where L is the given length of the rod. The mass of the rod will be m = p*V, where p is the density of copper, which is 8960 kg/m^3. Finally, the weight will be W = mg, where g is acceleration due to gravity, which is 9.8 m/s^2.

2007-08-20 09:34:06 · answer #2 · answered by DavidK93 7 · 0 1

Pi x R^2 x L = volume
3.14 x (4cm)^2 x100cm=volume
3.14 x 16cm^2 x 100cm= 1600cm^3 ( add the exponents)
Cu (elemental) weighs 8.96 gm/cm^3
1600cm^3 x 8.96gm= 14336 grams
one gram =.00220 pounds
14336 gm x .00220=31.54 pounds

there ya go...Good luck from the E

2007-08-20 09:57:44 · answer #3 · answered by Edesigner 6 · 0 0

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