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2007-08-19 04:35:39 · 2 answers · asked by sony r 1 in Science & Mathematics Engineering

2 answers

I guess with what you asked this is what you need???

Cut-Off Frequency
F = 1/(2*PI()*SQRT(L*C)
Characteristic Impedance
Z = SQRT(L/C)

circuitcalculator.com/lcfilter.htm

here is where i got it...If you need to know how it works ask again....Good luck from the E....

2007-08-19 04:45:58 · answer #1 · answered by Edesigner 6 · 0 0

Typically, it's an inductor (L) and a capacitor (C) in series with an oscillating voltage source (a signal generator). The output is taken as the voltage across either the inductor or the capacitor, depending on the purpose.

2007-08-19 11:45:24 · answer #2 · answered by lithiumdeuteride 7 · 0 0

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