I have tried the system and it does not work. It may work in the short run, in the long run it does not, unless you have an unlimited amount of money and are playing on a no limit table. I have lost as many as 12 hands in a row playing BJ. Doubling my bet after each loss, during that stretch, would not have been possible.
2007-08-17 04:56:51
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answer #1
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answered by double_down111 4
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no its even worse for doubles split cause if u lost one of those u would have raise ur bet 4 or 8 x. Its not a great system but if u must use it best aplied to don't pass in craps
or player bet in baccarat cause those best even money bets in casino except if u can find a a single wheel with surrender or en prison which i have never seen but red are available in Europe. Those bets all under 2% house edge
Anti martingale could work if cimbined with counting. u raise ur bet after u won if there alot of faces and aces left in deck.
This allows u to bet the casinos' money when the odds favor u. I have been moderately succesful with this appraoach
Basic counting track cards in ur head 2-6 add1 789 no chanfe 10,j,q,k,a -1 the higher the count the better ur chances
also high counts make insurance a god bet. Fewer decks are better contant shufflers are to be avoided. Also if u get cut card thin 2 win. Also time braks to lv table during low counts can save u money 2. Tiping dealers often slows them down and gets them to let u skip routine decision like 20 ec and gives u more time to count. Good luck have fun
2007-08-17 06:20:54
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answer #2
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answered by Anonymous
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Dave, you seem to be on a different planet, lol.
No, it will not work. Even if you never had to double or split, it would only go 10 hands deep at a $5 minimum, $5,000 maximum table. And if you've never lost 10 hands in a row at blackjack, you haven't played much.
The casinos were built on streaks, more than anything. If the games did not get streaky, they would go broke from players using systems like this. If the matingale worked at blackjack or any game, they would have changed the rules to prevent it a long time ago.
2007-08-17 05:48:16
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answer #3
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answered by Vegas Matt 7
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A Martingale will never work in any situation, but Blackjack is one of the worst games to try to use it.
The reason is very simple. There are situations in blackjack where you are required by basic strategy to split your cards. (88 or AA, for example).
If you lose both hands of the split (or 3 out of four splits!), your Martingale progression will be destroyed.
2007-08-17 04:00:05
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answer #4
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answered by John F 6
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In theory, any system will work as there is no limitation.
In practical, however, you will need consider the following
i) the amount of capital that you have which determine how many string of losses you can afford. For example, if you have only $10, you can only afford to lose 2 times as when you lose the third time, you will not have the capital to bet the fourth time.
ii) the maximum size bet for the table. This will determine the maximum string of losses that you can have on that table.
2007-08-17 04:01:35
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answer #5
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answered by tancy2411 4
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If you use it in blackjack on black and red, you want to find a european table usually higher stakes have the no zero wheels.
Then you want to let a run start before you start your system.
Let black or red start a run of 5 times in a row and then start your system and you have a better chance with no beginning risk.
I have done this in a short system. Let a run of 5 start then
bet once. 10$
if you lose double 20$+10=30$
if you lose double 60$+10$=70$
if you lose double 140$+10 $=150$
after three doubles quit, winner or loser. That is your shot at it. you either win a bunch of 10$ hits or you lose all and quit.
maximum loss is 260$ but you have to lose 9 times in a row to lose all, or you win 10$ each spin.
2007-08-17 05:14:22
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answer #6
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answered by Father Ted 5
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Essentially, you must understand that each bet you make as a negative expectation (-EV). There is no way to make a bunch of -EV numbers add up to a +EV one. No way. None. Understand that before you gamble.
2007-08-17 08:39:24
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answer #7
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answered by Anonymous
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