If this is a homework question, then:
Q = mc(DeltaT)
Q = 9,000kg (1000g/1kg) (4.184J/g-C) (6C)
note: I hope you're talking temperature in C.
Q = 225,936,000 Joules
A joule is a watt-second.
2.8kw = 2,800 watts
225,936,000joules (1watt-second/1joules) / 2,800 watts
= 80,691.4 seconds
= 1,344 minutes
= 22.4 hours
(excluding losses or gains from ambient)
If you're talking about degrees F, then it's 12.45 hours.
2007-08-15 07:38:00
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answer #1
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answered by Anonymous
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The 2.5 kW heater on my hot-tub takes about 1 hour to raise the temperature 5 degF when the ambient temperature is around 70 degF. The tub holds approximately 1000 liters.
Given your pool with 9 times the volume, which translates to over 4.3 times the surface area, it will take a very long time to raise the temperature by 6 degrees (F), and depending on the ambient temperature it may never happen.
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2007-08-15 07:45:10
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answer #2
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answered by tlbs101 7
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This sounds like one of those crazy homework questions that teachers give you to shut you up for an hour or two!
Depends on the depth of the pool; the shape of the pool (long, narrow pools take less time to heat than perfectly square or round pools); what the pool is made of (rubber, plastic, wood surround, cement surround etc.); whether it is an 'above ground' pool or cement and tiled 'in ground pool'); the temperature outside (or inside if you're posh and have an indoor pool); what the pool is filled with (milk, water, alcohol?); the colour of the liquid (reflected light reacts differently); and whether the sides and floor are coated in algae or not (helps conserve heat).
Hmmmmm.
2007-08-15 07:46:30
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answer #3
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answered by Val G 5
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i hope you are pumping the water through the heater, i would probably say the heater isnt big enough. some spa pools have 8kw heaters in them and they are well less than 9000 litres
2007-08-15 07:37:52
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answer #4
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answered by Anonymous
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question incomplete
what is the surface area of water and the ambient temp in the pool room
2007-08-15 07:33:31
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answer #5
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answered by Anonymous
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