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2007-08-07 06:46:02 · 7 answers · asked by sidney g 1 in Science & Mathematics Engineering

7 answers

Lead has a density of 0.41 lb/in^3. A ton is 2000 lb, so it would have a volume of 2000 / 0.41 = 4878 in^3. I assume we're talking about English units rather than metric. If you meant a metric ton, get the density in kg/m^3 and divide 1000 kg (a metric ton) by that figure instead.

2007-08-07 06:51:09 · answer #1 · answered by DavidK93 7 · 1 0

Metric ton = 1000 kg.
Density of Lead = 11∙34 kg/ L

Density (D) = Mass (m) / Volume (V)
V = m / D
V = 1000 kg / 11∙34 kg/ L
V = 88∙183 421 52...
V ≈ 88∙18 L

2007-08-07 14:52:57 · answer #2 · answered by Sparks 6 · 0 0

The Specific Gravity of Lead = 11.34.
The S.G. of water = 1.0.
1 metric ton of water = 1 m³.
1m³ ÷ 11.34 = 0.088m³ = Volume of 1 ton of lead.

2007-08-07 23:33:11 · answer #3 · answered by Norrie 7 · 0 0

tricky question as it depends on the type of lead:

Lead, commercial, 1 cubic foot weighs 125-140 lbs
Lead, ores, 1 cubic foot weighs 710 lbs
Lead, scrap, 1 cubic foot weighs 200-270 lbs

2007-08-07 14:00:25 · answer #4 · answered by Indiana Frenchman 7 · 0 0

density of Pb =11.35 g/cm^3

so 1ton = 10^6g

the volume is 10^6/11.35 =88,105 cm^3= 0.088105m^3

2007-08-07 13:58:53 · answer #5 · answered by maussy 7 · 0 0

general eng handbook, find the weight for a cubic foot of lead, into 2000=volume. ok, send me $20 bucks. lol

2007-08-07 13:50:46 · answer #6 · answered by Anonymous · 0 2

divide by density in appropriate units

2007-08-07 13:51:09 · answer #7 · answered by jbowers9 1 · 0 0

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