When a schematic shows multiple grounds, do the grounds need to be electrically isolated from each other?
Also, I've seen implementations where the ground is really just wire connected to the chassis. Why does this work when leaving the wire unconnected doesn't work? Does it have something to do with capacitance?
2007-08-06
05:50:08
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5 answers
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asked by
Brent L
5
in
Science & Mathematics
➔ Engineering
Thanks to those who have answered so far, but you seem to have missed the point of the second part of my question:
The only difference between connecting the chassis to the circuit, and leaving the circuit unconnected, is that when the circuit is connected, there's an extra chunk of metal at the connection point. Instead of just a solder point, there's a wire, with a chunk of metal, the chassis, at the end of that wire. Why should it matter that there's an extra chunk of metal there? What is the physical mechanism that makes the difference? Is it a capacitive effect? Inductive, maybe? What is the minimum necessary size?
2007-08-06
08:14:11 ·
update #1
I mean, the circuit won't work if you just connect the ground points together without any sort of ground, will it? What if only one ground is necessary? It won't work to just leave the circuit disconnected from a ground (if the schematic calls for it), right? Then how massive a hunk of metal does the ground need to be?
2007-08-06
08:19:33 ·
update #2