The height of a box is 4 inches. The length is three inches more than the width. Find the width if the volume is 432.
2007-08-05 12:17:43 · 4 answers · asked by Jose T 1 in Science & Mathematics ➔ Engineering
Height = 4
Width = W
height = W + 3
Volume = height x Length x Width = 432
4 x W x (W+3) = 432
4WxW + 4Wx3= 432
4 W squared + 12W - 432 = 0
W squared + 3w -108 = 0
Factoring you get
(W-9)(W+12) = 0
W can be either 9 or -12.
Since it can't be negative number, Width must = 9 inches
2007-08-05 16:01:53 · answer #1 · answered by Rich Z 7 · 0⤊ 0⤋
w= Width, w+3= Length, Height=4 Volume=432=HWL so:
4w(w+3)=432
4w^2+12w-432=0
w^2+3w-108=0
(w+12)(w-9)=0
w=9 inches
2007-08-05 12:21:41 · answer #2 · answered by 037 G 6 · 0⤊ 0⤋
WHL = 432; H = 4, so WL = 108. L = W+3, so we have W(W+3) = 108, or W^2 + 3W -108 = 0. This easily solves to give W = 9 or -12.
2007-08-05 12:22:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋
That sounds exactly like my homework! What a coincidence!
Trust me, you shouldn't rely on other people to give you answers on a silver mathbook...er...I mean platter.
2007-08-05 12:39:29 · answer #4 · answered by ZomToad 2 · 0⤊ 0⤋