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I did not explain myself correctly last night.Each and every shot I take in properties it shows digital focal length among shutter speed, aperture etc. Want to know in each and every shot I take what would be the equivelent 35MM focal length. With the Sony it seemed about right, times each digital focal length by 6 to get equivelent 35mm focal length. Sensor 1/2.5,12X optical,6 megapixels. What would I times fuji with each shot? 4x optical, 9 megapixels, and sensor 1/1.6
Maybe take my old 35mm Nikon FE2 and compare focal lengths and then times by a certain number?Antoni and Dr. Sam sorry I did not explain my question correctly last night.

2007-08-03 03:47:24 · 2 answers · asked by Vintage Music 7 in Consumer Electronics Cameras

2 answers

I posted this in your original question just a few minutes ago, but here it is again for convenience:

Your E900 has a 1/1.6" sensor measuring about 8mm x 6mm. The sensor to compare with measures 36mm x 24mm. Divide the larger length by the smaller length, then do the same for width: 36/8=4.5 and 24/6=4. The discrepancy is due to differing aspect ratios, the smaller sensor being 4:3 while the larger one is 3:2. For differing aspect ratios, the length multiplier is normally used to calculate the 35mm equivalent, and in the case of a 1/1.6" sensor, that's 4.5 (it's actually 4.4444444444 but what's a few decimals).

2007-08-03 04:11:15 · answer #1 · answered by Anonymous · 0 1

i thought Dr sam answered it? I gave you the original formula and the DR quite rightly applied it to your camera/lens/sensor equation

what was it 32mm then times by the zoom factor?

eg it says zoom 2.0

then 32mm x 2 = 64mm (thats if i understand it)

give us an example reading of the focal lenght (Fstop,shutter etc dont matter.

good idea to do the comparasion then you will learn and find out yourself - you know - i do i understand, i see i believe, i hear i forget

ah FE2 what a loverly ring to it



a

2007-08-03 11:23:38 · answer #2 · answered by Antoni 7 · 0 1

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