inside or outside of the ladders base and how thick is the base?
2007-07-27 16:45:41
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answer #1
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answered by Ronko 4
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think of of it like a triangle and use the Pythagorean Theorem, that's a^2 + b^2 = c^2. the 1st time the ladder is sixteen ft long and eight from the backside. because of the fact the development and the floor make a real perspective, the section opposite (the ladder itself) is the hypotenuse (c^2). section a is the gap the ladder is from the development (8 ft). So for that one it may be 8^2 + b^2 = sixteen^2. To get b^2 subtract 8^2 from sixteen^2 (256-sixty 4) the respond is 192 and the sq. root of that's section b (thirteen.86). Do the comparable factor for the recent subject, the place section a is 4 ft somewhat, so 4^2 + b^2 = sixteen^2. utilising the comparable steps, sixteen^2 - 4^2 = b^2. (256-sixteen) the respond is 240 and the sq. root of that's section b (15.40 9). Subtract the 1st answer from this to work out how lots greater the ladder is now. 15.40 9-thirteen.86=a million.sixty 3 wish you recognize and that grew to become into useful!
2016-12-11 03:55:44
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answer #2
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answered by Anonymous
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(7*7) + (h*h ) = 15 *15
49 *h*h = 225
h*h = 225 - 49 = 176
h = 13.26649
h = 13.27
this problem is a simple right triangle problem
the sum of the squares of the two sides = square of the hypontenuse
15 ^2 = 7^2 + height ^2
2007-07-27 16:47:39
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answer #3
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answered by mark 6
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Its simple math, called Pythagoras's theorem.
The square of the hypotenuse (the long angled side) is equal to the sum of the square of the other 2 sides.
h^2 = a^2 + b^2.
You know h (the hypotenuse) - 15 ft. Square that.
You know a (one of the other sides) - 7 ft. Square that.
So 225 = 49 + b^2. Just solve for b.
2007-07-27 16:40:45
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answer #4
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answered by Anonymous
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13.27 feet high
It is the usual Pythagorean rule for a right triangle.
c squared = a squared plus b squared.
The hypotenuse c = 15 so c squared = 225
The bottom a = 7 so a squared = 49
b squared = 225-49 = 176
b = square root of 176 = 13.27 ft which is height reached.
2007-07-27 17:00:50
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answer #5
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answered by Rich Z 7
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It's just simply triangle equation. c^2=a^2+b^2
where c is the hypotenuse, length of ladder = 15
a is the one side of triangle = 7
b is the other side to be unknown
therefore,
b^2=c^2-a^2
b= sqrt of (15^2-7^2)
b= 13.27 ft.
2007-07-28 00:34:20
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answer #6
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answered by akpy pogi 1
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let the top of ladder is x feet above the ground ie top the ladder from ground.
so we can write from traingle rule
15^2=x^2+7^2
or 225=x^2+49
or x^2=225-49
or x^2=176
or x=sqrt 176
or x=13.27feet (approx),
ie the top of the ladder is 13.27 feet from ground (the answer)
2007-07-27 19:53:18
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answer #7
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answered by zonaith 2
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h = (15^2 -7^2)^.5 = (225 - 49)^.5 = 176^.5 = 13.27'
2007-07-27 17:11:46
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answer #8
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answered by mechnginear 5
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Depends on whether the ground is level. Does the wall and the ground create a right angle? It's about 13.25' if it's a right angle.
Good luck.
2007-07-27 16:50:48
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answer #9
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answered by amistere4u 3
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15^2=x^2+7^2
hence answer: x=13.266
2007-07-27 17:37:45
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answer #10
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answered by Raj 1
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