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a 15 ft ladder leans against a building. the bottom of the ladder is 7 ft from building. how high is the top of the ladder? round to 2 decimal places

2007-07-27 16:33:30 · 13 answers · asked by david b 1 in Science & Mathematics Engineering

13 answers

inside or outside of the ladders base and how thick is the base?

2007-07-27 16:45:41 · answer #1 · answered by Ronko 4 · 0 1

think of of it like a triangle and use the Pythagorean Theorem, that's a^2 + b^2 = c^2. the 1st time the ladder is sixteen ft long and eight from the backside. because of the fact the development and the floor make a real perspective, the section opposite (the ladder itself) is the hypotenuse (c^2). section a is the gap the ladder is from the development (8 ft). So for that one it may be 8^2 + b^2 = sixteen^2. To get b^2 subtract 8^2 from sixteen^2 (256-sixty 4) the respond is 192 and the sq. root of that's section b (thirteen.86). Do the comparable factor for the recent subject, the place section a is 4 ft somewhat, so 4^2 + b^2 = sixteen^2. utilising the comparable steps, sixteen^2 - 4^2 = b^2. (256-sixteen) the respond is 240 and the sq. root of that's section b (15.40 9). Subtract the 1st answer from this to work out how lots greater the ladder is now. 15.40 9-thirteen.86=a million.sixty 3 wish you recognize and that grew to become into useful!

2016-12-11 03:55:44 · answer #2 · answered by Anonymous · 0 0

(7*7) + (h*h ) = 15 *15

49 *h*h = 225
h*h = 225 - 49 = 176
h = 13.26649
h = 13.27

this problem is a simple right triangle problem

the sum of the squares of the two sides = square of the hypontenuse

15 ^2 = 7^2 + height ^2

2007-07-27 16:47:39 · answer #3 · answered by mark 6 · 1 0

Its simple math, called Pythagoras's theorem.
The square of the hypotenuse (the long angled side) is equal to the sum of the square of the other 2 sides.
h^2 = a^2 + b^2.

You know h (the hypotenuse) - 15 ft. Square that.
You know a (one of the other sides) - 7 ft. Square that.
So 225 = 49 + b^2. Just solve for b.

2007-07-27 16:40:45 · answer #4 · answered by Anonymous · 1 0

13.27 feet high

It is the usual Pythagorean rule for a right triangle.

c squared = a squared plus b squared.

The hypotenuse c = 15 so c squared = 225
The bottom a = 7 so a squared = 49

b squared = 225-49 = 176

b = square root of 176 = 13.27 ft which is height reached.

2007-07-27 17:00:50 · answer #5 · answered by Rich Z 7 · 0 0

It's just simply triangle equation. c^2=a^2+b^2
where c is the hypotenuse, length of ladder = 15
a is the one side of triangle = 7
b is the other side to be unknown

therefore,
b^2=c^2-a^2
b= sqrt of (15^2-7^2)
b= 13.27 ft.

2007-07-28 00:34:20 · answer #6 · answered by akpy pogi 1 · 0 0

let the top of ladder is x feet above the ground ie top the ladder from ground.
so we can write from traingle rule
15^2=x^2+7^2
or 225=x^2+49
or x^2=225-49
or x^2=176
or x=sqrt 176
or x=13.27feet (approx),
ie the top of the ladder is 13.27 feet from ground (the answer)

2007-07-27 19:53:18 · answer #7 · answered by zonaith 2 · 0 0

h = (15^2 -7^2)^.5 = (225 - 49)^.5 = 176^.5 = 13.27'

2007-07-27 17:11:46 · answer #8 · answered by mechnginear 5 · 1 0

Depends on whether the ground is level. Does the wall and the ground create a right angle? It's about 13.25' if it's a right angle.
Good luck.

2007-07-27 16:50:48 · answer #9 · answered by amistere4u 3 · 0 0

15^2=x^2+7^2

hence answer: x=13.266

2007-07-27 17:37:45 · answer #10 · answered by Raj 1 · 0 0

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