2007-07-25 19:23:13 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Given
(x² - 9)/2y = (x - 3)/4
We factor out
(x + 3)(x - 3)/2y = (x - 3)/4
Then, since x ≠ 3, x - 3 ≠ 0 therefore we can divide both sides by x - 3...
(x + 3)/2y = 1/4
We cross multiply
4x + 12 = 2y
Divide both sides by 2
2x + 6 = y
Transpose 6
2x = y - 6
Then divide by 2 again! Therefore...
x = (y - 6)/2
Hope this helps!
2007-07-25 20:31:40 · answer #1 · answered by kevin! 5 · 0⤊ 0⤋
x = y/2 - 3
2007-07-26 02:29:49 · answer #2 · answered by Helmut 7 · 0⤊ 1⤋
(x^2-9)/2y = (x-3)/4
(x+3)(x-3)/2y = (x-3)/4
(x+3)/y = 1/2
y = 2(x-3)
2007-07-26 02:35:27 · answer #3 · answered by lil boosie 4 · 0⤊ 1⤋
[(x-3) (x+3)/2y]/(x-3) = [(x-3)/4]/(x-3)
(x+3)/2y = 1/4 (cross multiply)
4(x+3) = 2y
4x+12 = 2y
4x= -2y+12
x = -0.5y+3
2y = -4x+12
y = -2x+6
2007-07-26 03:02:56 · answer #4 · answered by ghelo_madrid91591 1 · 0⤊ 0⤋
(x^2 - 9) / 2y =(x - 3) / 4
or, (x+3)(x - 3) / 2y = (x - 3) / 4
or, (x+3) / y = 1 / 2
or, 2x + 6 = y
or, x = (y - 6) / 2
2007-07-26 02:53:17 · answer #5 · answered by kajal 1 · 0⤊ 0⤋