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8 answers

Hey there!

Here's the answer.

2x+3y=20 --> Write the problem.
2x+3(2)=20 --> Substitute 2 for y.
2x+6=20 --> Multiply 3 and 2.
2x=14 --> Subtract 6 on both sides of the equation.
x=7 Divide 7 on both sides of the equaton.

Check to see whether the solutions satisfy the equation.

2(7)+3(2)=20 -->
14+6=20 -->
20=20, true.

Since the solutions satisfy the equation, the solution set is {7,2}. If you want to write it in the form of an ordered pair, it would be like this (7,2).

Hope it helps!

2007-07-26 05:17:19 · answer #1 · answered by ? 6 · 0 0

2x + 3y= 20 when y = 2

2x + 3(2) = 20
2x + 6 = 20
2x = 20 -6
2x = 14
x = 7

(x, y) = (7, 2)

Checking the answer:
2x + 3y= 20
2(7) + 3(2) = 20
14 + 6 = 20
20 = 20. Check.

2007-07-25 19:24:31 · answer #2 · answered by Reese 4 · 1 0

Okay, first solve the equation.
2x + 3y= 20 when y = 2
Substitute 2 for y in the equation:
2x + 3(2)=20
Simplify:
2x+6=20
Subtract 6 on both sides to isolate the variable:
2x+6=20
-6 -6
2x=14
Divide both sides by 2:
x=7

So, when y=2, x=7
The ordered pair, written in the form (x,y), would be (7,2)

2007-07-25 19:26:47 · answer #3 · answered by sanu babii <3 1 · 1 0

Well the best I can do is 2(7)+3(2)=20 7,2ordered pair

2007-07-25 19:32:04 · answer #4 · answered by Miss Breaux 1 · 1 0

2x + 6 = 20
2x = 14
x = 7
Solution is (7, 2)

2007-07-25 22:07:44 · answer #5 · answered by Como 7 · 0 0

2x + 3(2) = 20
2x + 6 = 20
2x = 14
x = 7

Ordered Pair (x,y) (7,2)

2007-07-25 19:25:24 · answer #6 · answered by marcellus 2 · 1 0

2x+6=20
2x=14
x=7

plug.(7) into x

14+6=------> "20"

2007-07-25 19:33:04 · answer #7 · answered by Anonymous · 1 0

2x + 3y= 20 when y = 2

ordered pair is

(7,0) (0,2)

2007-07-25 19:29:46 · answer #8 · answered by babylala_luvs_ya 3 · 0 0

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