x + y + z = 9
w + y + z= 5
w + x = 2
what is the average of w, x , y, and z?
(a) 0
(b) 1
(c) 2
(d) 3
(e) 4
2007-07-25 18:56:41 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2
2007-07-25 19:05:36 · answer #1 · answered by Tom 3 · 0⤊ 0⤋
(x + y + z) + (w + y + z) + (w + x)= 9 + 5 + 2
(* Simplify LHS and RHS *)
2w + 2x + 2y + 2z = 16
(* Divide by 2 *)
w + x + y + z = 8
To find the average " add & divide"
The sum of w, x, y, z is 8
8 divided by the 4 items is 2
2007-07-25 19:10:47 · answer #2 · answered by marcellus 2 · 0⤊ 0⤋
c
add eq 1&2 to get :
w+x+2y+2z=14
2+2y+2z=14
y+z=6
w+x+y+z=2+6=8
Avg = 8/4=2
2007-07-25 19:18:17 · answer #3 · answered by 037 G 6 · 0⤊ 0⤋
x - w = 4
x + w = 2
2x = 6
x = 3
w = - 1
3 + y + z = 9
y + z = 6
Average of x, y, w, z = (3 - 1 + 6) / 4 = 2
ANSWER (c)
2007-07-25 22:22:59 · answer #4 · answered by Como 7 · 0⤊ 0⤋
x=3
w=-1
y+z = 6
therfore
w+x+y+z=8
ave=2
c is the answer
2007-07-25 19:03:42 · answer #5 · answered by wagnavu 2 · 1⤊ 0⤋