What linear equation describes the line that passes through (0, -4) and (3, 2)?

Question

Here is your options:
A. y= 2x-4
B. y= -2x+3
C. y= 3x-2
D. y= -4x+2

these are not sat questions, just trying to solve them from a math class i'm taking. I'm sorry math is the only subject I am extremely horrible at. Thanks everyone for helping out.

Answer 1

m = (2 + 4) / (3 - 0) = 6 / 3 = 2
y - 2 = 2 (x - 3)
y - 2 = 2x - 6
y = 2x - 4
ANSWER A

Answer 2

(0,-4) and (3,2)

Formula for finding the equation of the line if two points are known is
(y - y1)/ (x - x1) = (y2 - y1)/ (x2 - x1)

[y -(-4)]/[ x - 0] = [2 - (-4)] / [3 - 0]

[y + 4]/ x = [2 + 4] / 3

[y + 4]/ x = 6 / 3

3y + 12 = 6x

Dividing throughout by 3,

y + 4 = 2x

y = 2x - 4

Therefore the answer is (A) y = 2x - 4

Answer 3

A. y= 2x-4
slope = (-4-2)/(0-3) = 2
y-intercept = -4 (since x=0)

therefore: y=2x-4

Answer 4

Slope = (change in y) / (change in x)
= (2+4)/(3-0)
= 2

A is the only option with a slope of 2, but I will complete the solution anyway.

y= mx + c
It passes through (3,2)
2 = 6 + c
c = -4
y = 2x - 4

A

Answer 5

Find the slope first (2--4)/(3-0) and then you'll realize that it has to be A because that's the only one with 2 as your slope

Answer 6

a

If this were a SAT problem, I would suggest a quick trial and error rather than actually setting up a solution.

Start with the first equation and the first set of points and see if they satisfy. If so, try the second set. If they satisfy, that's the answer, don't even go on.

If the first set doesn't satisfy the equation, go immediately to the next answer choice and start over with the first set of points.

This method will save you appreciable time.