im struggling with this math.
The perimeter of a triangle is 7a-11b.If two of its sides are 2a+b and a-9b,what is the third side
*hint*_ _ _ _ b
2007-07-25 18:17:49 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Shouldn't be that hard. The perimeter is the sum of THREE sides.
So 7a-11b = (2a+b) + (a-9b) + third side.
Since a and b are separate variables, you can separate the problem and solve for a and b.
third side = 4a - 3b
2007-07-25 18:22:56 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
Perimeter 7a-11b
One side=2a+b
Another side =a-9b
Total of this=3a-8b
Deducting this from total perimeter 7a-11b
- 3a-8b
=4a-3b
2007-07-25 18:34:53 · answer #2 · answered by Prabhakar G 6 · 0⤊ 0⤋