2007-07-25 17:36:07 · 5 answers · asked by BJ G 1 in Science & Mathematics ➔ Mathematics
No, a circle will not pass the vertical line test...
Unless, we separate the circle into two functions;
y1=+sqrt(25-x^2) the upper part of the circle
y2=-sqrt(25-x^2) the lower part of the circle
2007-07-25 17:40:03 · answer #1 · answered by espms290 4 · 2⤊ 0⤋
No, it is not.
An equation is not a function if a value of X has more than one Y value. In the case of a circle, you can easily see that would be the case so no circle is a function.
2007-07-26 00:42:12 · answer #2 · answered by bimeateater 7 · 1⤊ 0⤋
the equation represents a circle
rewrite the equation in terms of y for it to be a function
y= sqrt(25 - x^2)
2007-07-26 00:38:48 · answer #3 · answered by superman 4 · 0⤊ 1⤋
Not in this form. You can wind up with a function of y= f(x); however, it is a two-valued function.
2007-07-26 00:39:20 · answer #4 · answered by cattbarf 7 · 0⤊ 2⤋
no! read about the vertical line test.
2007-07-26 01:13:55 · answer #5 · answered by william b 2 · 0⤊ 0⤋