2007-07-25 16:51:45 · 10 answers · asked by cmc 1 in Science & Mathematics ➔ Mathematics
divide 2.5 into 18.66
so (56/3) / (5/2)=
(56/3) x (2/5)=
112/15=
7.46
since .46 isn't a whole package, you are left with 7 packages
2007-07-25 16:54:47 · answer #1 · answered by jnice160 2 · 0⤊ 0⤋
18 2/3=56/3 and 2 1/2 = 5/2 therefore 56/3 divided by 5/2 =7.5packages round up and the # of packages are 8
2007-07-25 23:56:45 · answer #2 · answered by Meg 2 · 0⤊ 1⤋
18 2/3 = 56/3
2 1/2 =5/2
divide:
(56/3)/(5/2) = (56/3)(2/5) = 112/15 = 7 remainder 7
7 packages of 2 1/2 lbs remainder 7/15 lbs
2007-07-26 00:09:50 · answer #3 · answered by ferdie 2 · 0⤊ 0⤋
7
2007-07-25 23:54:44 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2 and 1/2 into 18 and 2/3 goes 7 times with 1 and 1/6 over
7 packs with leftovers of 1 and 1/6 pounds
2007-07-26 05:55:54 · answer #5 · answered by rosie recipe 7 · 0⤊ 0⤋
(18 2/3) / (2 1/2) =
((3*18 + 2)/3) / ((2*2 + 1)/2) =
(56/3) / (5/2) =
(56/3)*(2/5) =
112 / 15 =
7 + 7/15
2007-07-26 00:10:45 · answer #6 · answered by Helmut 7 · 0⤊ 0⤋
2/3 = 0.666. and 1/2 = 0.5
18.666 ÷ 2.5 = 7 packs and ½ lb to fry up now.
2007-07-26 00:07:24 · answer #7 · answered by Norrie 7 · 0⤊ 0⤋
18.75/2.5=7.5=8 packages
2007-07-26 00:12:06 · answer #8 · answered by arkwrite 1 · 0⤊ 0⤋
Boring. Ask another.
2007-07-26 00:22:39 · answer #9 · answered by mailliam 6 · 0⤊ 1⤋
Are you trying to get us to do your homework?
2007-07-25 23:59:00 · answer #10 · answered by happybidz2003 6 · 0⤊ 1⤋