fraction help please :]?

Question

okay welllll i have a algebra 2 math final tomorrow and I really don't know how to do these two problems, just please try to help me as much as you can, thanks if advance! :)

x^2 -2x-8=4

and

1- 4 over x+6 = 4 over x

Answer 1

x^2 - 2x - 8 = 4
<=> x^2 - 2x - 12 = 0
The discriminant Δ = b^2 - 4ac = 4 - 4(1)(-12) = 52 is not a square, so the solutions are irrational.
<=> x = (2 ± √52) / 2
= 1 ± √13.

I assume for the second one you mean
1 - 4 / (x+6) = 4 / x
Multiply through by x(x+6):
<=> x(x+6) - 4x = 4(x+6), x ≠ 0, -6.
<=> x^2 - 2x - 24 = 0, x ≠ 0, -6
<=> (x-6) (x+4) = 0, x ≠ 0, -6
<=> x = 6 or -4.