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(3/11, -1/11)?? is this correct

2007-07-25 14:03:29 · 2 answers · asked by Jacesmom 2 in Science & Mathematics Mathematics

2 answers

I am afraid you are wrong
3x^2=11+32x
or,3x^2-32x-11=0
or,3x^2-33x+x-11=0
or,3x(x-11)+1(x-11)=0
or,(x-11)(3x+1)=0
therefore,either x-11=0 or 3x+1=0
If x-11=0,then x=11
If 3x+1=0,then 3x= -1 or x= -1/3
hence x=11 or -1/3

2007-07-25 14:07:28 · answer #1 · answered by alpha 7 · 0 0

Hello

Put them all on the right side and we have

0 = 3x^2 -32x -11 factor and get 0 = 3x^2 -33x +1x -11 or 3x(x-11) +1(x - 11) = 0 so 3x+1 = 0 or x = -1/3 and x = 11.

Hope This Helps!

2007-07-25 14:12:44 · answer #2 · answered by CipherMan 5 · 0 0

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