5x(squared) -45x = -100
5x(squared) -45x +100 = 0
x(squared) -9x +20 = 0
(x-5)(x-4) = 0
x=5 x=4
Solved!
2007-07-25 12:33:39
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answer #1
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answered by Emmet F 2
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5x(x-9) = -100
5x^2 - 45x = -100
5x^2 - 45x + 100 = 0
(5x-25)(x-4) = 0
Solve each factor
5x - 25 = 0
5x = 25
x = 5
x - 4 = 0
x = 4
Therefore x = 4 and x = 5 are the answers
2007-07-25 12:32:38
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answer #2
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answered by kousuke51 2
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5x² - 45x + 100 = 0
x² - 9x + 20 = 0
(x - 5) (x - 4) = 0
x = 4 , x = 5
2007-07-26 07:12:40
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answer #3
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answered by Como 7
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5x(x) - 5x(9)= -100
5x^2 - 45x = -100
5x^2 - 45x + 100 = 0 ../5
x^2 - 9 x + 20 =0
(x-5) (x-4) = 0
x=5 or x=4
2007-07-25 12:42:57
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answer #4
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answered by iwan s 1
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You are kidding, right?
(1) Multiply both sides by 1/5
(2) Multiply the left side out.... you know... distributive property.
(3) Add the negative of whatever is on the right side to both sides.
(4) Now you should be able to factor it easily.
2007-07-25 12:39:41
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answer #5
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answered by gugliamo00 7
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5x(x-9)=-100
5x^2-45x+100=0
x^2-9x+20=0
x^2-9x+20=(x-4)(x-5)
x=4 and x=5
2007-07-25 12:35:09
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answer #6
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answered by davidrufus1701 3
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123
2007-07-25 12:30:21
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answer #7
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answered by pochocrdv 2
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Simplify: (5/2y)³
2014-12-16 14:49:36
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answer #8
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answered by Anonymous
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5x+x(exponent 2)-45+ x-9
i think
2007-07-25 12:32:22
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answer #9
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answered by aryatack 3
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