Can someone show me how to find the integral of:
sin(sqrt(x)) dx.
Thanks!
2007-07-25 12:21:37 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Set t:=sqrt(x), so dt=dx/(2*sqrt(x)). Your integral reads:
\int 2t*sin(t) dt
then by parts:
\int 2t*sin(t) = -2t*cos(t) + 2*sin(t)
and getting back to x you have:
\int sin(sqrt(x))dx = -2sqrt(x)*cos(sqrt(x)) + 2*sin(sqrt(x))
Bye!
2007-07-25 12:52:13 · answer #1 · answered by Anonymous · 0⤊ 0⤋
integral of:
sin(sqrt(x)) dx.
integrate function of a function
http://www.hostsrv.com/webmaa/app1/MSP/webm1001/Integrate
use this site, it won't let me give you the answer sorry
2007-07-25 19:41:13 · answer #2 · answered by davidrufus1701 3 · 0⤊ 0⤋
= -cos(sqrt(x)) * (-1/(2*sqrt(x))
2007-07-25 19:33:58 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋