Factor the quadratic expression:
w^2 + 8w +16
Thanks for the help!!
2007-07-25 12:21:30 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(w + 4)(w + 4)
2007-07-25 12:25:24 · answer #1 · answered by McFate 7 · 0⤊ 1⤋
w^2 + 8w +16
= w^2 + 4w + 4w + 16
= w(w+4) + 4(w+4)
= (w+4)^2
You coud recognize that the equation is in the form of
x^2 + 2xy + y^2 = (x+y)^2
w^2 + 8w +16
= w^2 + 2*4*w + 4^2
= (w+4)^2
2007-07-25 19:27:12 · answer #2 · answered by gudspeling 7 · 0⤊ 0⤋
8/2 = 4
4^2 = 16
w^2 + 8w +16 =
(w + 4)^2
2007-07-25 19:26:40 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
(w +4)^2
2007-07-25 19:28:45 · answer #4 · answered by pearlysim 1 · 0⤊ 0⤋
= (w + 4) (w + 4)
= (w + 4) ²
2007-07-28 05:26:28 · answer #5 · answered by Como 7 · 1⤊ 0⤋
w² + 8w +16
Learn this form. It’s one of a few you need…
a² + 2ab + b² = (a + b)²
In this case a = w and b = 4
So the factors are
(w + 4)(w + 4) or (w + 4)²
2007-07-25 19:31:00 · answer #6 · answered by gugliamo00 7 · 0⤊ 0⤋
(w+4) x (w+4)
Use the FOIL method.
First
Outer
Inner
Last
2007-07-25 19:29:43 · answer #7 · answered by Anonymous · 0⤊ 0⤋
(w+4) x (w+4)
Use the FOIL method.
2007-07-25 19:29:59 · answer #8 · answered by ethebest123456789 2 · 0⤊ 0⤋