3
∑ (3i + 1) find the value
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2007-07-25 11:20:22 · 6 answers · asked by jessie0420 2 in Science & Mathematics ➔ Mathematics
21
2007-07-25 11:23:18 · answer #1 · answered by Michael J 1 · 1⤊ 1⤋
Sum(mation) of (3i+1) from i=1 to i=3:
(3x1 + 1) + (3x2 + 1) + (3x3 + 1) = 4 + 7 + 10 = 21
2007-07-25 11:27:36 · answer #2 · answered by williamh772 5 · 0⤊ 0⤋
3
â (3i + 1) = (3*1 + 1) + (3*2 + 1) + (3*3 + 1) = 4+7+10 = 21
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2007-07-25 11:28:26 · answer #3 · answered by buoisang 4 · 0⤊ 0⤋
i=1 -> 3*1 + 1 = 4
i=2 -> 3*2 + 1 = 7
i=3 -> 3*3 + 1 = 10
4 + 7 + 10 = 21
2007-07-25 11:25:24 · answer #4 · answered by McFate 7 · 1⤊ 0⤋
It's not a trig problem. It's simply a summation, a shorthand for:
(3x1 + 1) + (3x2 + 1) + (3x3 + 1)
You substitute each of the integer values from 1 to 3 inclusive for i and add up all the resultant expressions.
2007-07-25 11:24:58 · answer #5 · answered by Raichu 6 · 1⤊ 0⤋
it's 21!!!
2007-07-25 11:40:29 · answer #6 · answered by Mitsuki 2 · 0⤊ 0⤋