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2007-07-25 09:20:53 · 6 answers · asked by datfreshness 1 in Science & Mathematics Mathematics

6 answers

sqrt(75)+sqrt(3)

sqrt(25*3) + sqrt(3)

sqrt(25)*sqrt(3) + sqrt(3)

5*sqrt(3) + sqrt(3)

6*sqrt(3)

2007-07-25 09:23:29 · answer #1 · answered by Andrew 4 · 1 1

8 square root of 3

75 is 25*3 and the square root of 25 is 5, so the square root of 75 is 5 square root of 3. Now add 3 to 5, and you have 8 square root of 3

2007-07-25 09:25:45 · answer #2 · answered by Katie 3 · 0 1

√(75) + 3
√(25)√(3) + 3

5√(3) + 3

2007-07-25 09:33:50 · answer #3 · answered by MathGuy 6 · 0 0

remember, you will desire to have straightforward gadgets to characteristic or subtract. the 'straightforward unit' to that end would desire to be sqrt 3, in any different case they are able to't be blended. sqrt seventy 5 = sqrt(25 x3)= sqrt 25 x sqrt 3 = 5 sqrt 3 now you have 5sqrt 3 + a million sqrt 3 which equals 6 sqrt 3.

2016-12-14 17:56:59 · answer #4 · answered by Anonymous · 0 0

Do you mean:
sqrt(75) + sqrt(3) ?

If so...

sqrt(75) + sqrt(3) =
sqrt(25*3) + sqrt(3) =
5*sqrt(3) + sqrt(3) =
6 * sqrt(3)

2007-07-25 09:26:03 · answer #5 · answered by McFate 7 · 1 0

=sq rt(75)+sq rt(3)
=sq rt(3*5*5)+sq rt(3)
=sq rt(3*5^2)+sq rt(3)
=5 sq rt(3)+sq rt(3)
=sq rt(3){5+1}
=sq rt(3){6}
=6 sq rt(3) ans

2007-07-25 09:29:22 · answer #6 · answered by MAHAANIM07 4 · 0 0

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