i need help plz!!! Solve the equation by factoring?

Question

1. x²+13x+30=0 2. x²-19x+84=0 3. x²-34x-240=0


4. 2x²+15x-108=0 5. 9x²-9x=28 6. 18x²-57x= -35

Answer 1

1.) (x + 10)(x + 3) = 0
x = -10, -3

2.) (x - 12)(x - 7) = 0
x = 12, 7

3.) (x - 40)(x + 6) = 0
x = 40, -6

4.) 2x^2 + 24x - 9x - 108 = 0
2x(x + 12) -9(x + 12) = 0
x = -12, 9/2

5.) 9x^2 - 21x + 12x - 28 = 0
3x(3x - 7) +4(3x - 7) = 0
x = 7/3, -4/3

6.) 18x^2 - 57x + 35 = 0
18x^2 - 42x - 15x + 35 = 0
6x(3x - 7) -5(3x - 7) = 0
x = 7/3, 5/6

Suppose the general formula of a quadratic eq. is ax^2 + bx + c, where a, b and c are constants. To factor the eq., u have to split b into two number whose sum is b and product equals the product of a and c.

Answer 2

1. (x + 10)*(x + 3)
2, (x - 12)*(x - 7)
3. (x - 40)*(x + 6)
4. (2x - 9)*(x + 12)
5. (3x - 7)*(3x + 4)
6. (6x - 5)*(3x - 7)

I hope these are good. It's almost 4:30 in the morning where I am so I'm getting a little tired. They look OK to me. Good luck.

Answer 3

1. (x+10)(x+3) x= -10 and -3
2. (x-7)(x-12) x=7 and 12
3. (x-40)(x+6) x=40 and -6
4. (2x+9)(x-12) x= -9/2 and 12
5. (3x+4)(3x-7) x= -4/3 and 7/3
6. (3x-7)(6x-5) x= 7/3 and 5/6

Hope that is what you are looking for.

Answer 4

1. (x+10)(x+3)=0, x=-10,-3
2.(x-12)(x-7)=0, x=12,7
3.(x-40)(x+6)=0, x=40,-6
4.(2x-9)(x+12)=0, x=9/2, -12
5.(3x-7)(3x+4)=0, x=7/3,-4/3
6.(6x-5)(3x-7)=0, x=5/6,7/3