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Solve: If 0.1 mol of reach compound is dissolved in water, which one contains 0.2 mol of solute particles, which one contains 0.1 mole of solute particles, and which contains between 0.1 and 0.2 mol of solute particles? Write equations to show reasoning?

2007-07-25 08:08:08 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

CH3COCH3(aq) --> CH3COCH3(aq) (doesn't ionize conc(final) = conc(initial)) = 0.1 M

2HClO(aq) --> H+(aq) + ClO-(aq) + HClO(aq) (some ionizes conc (final) > conc (initial)) = between 0.1 M and 0.2 M

NH4Cl(aq) --> NH4+(aq) + Cl-(aq) (all ionizes conc (final) = 2 conc (initial)) = 0.2 M

2007-07-25 08:19:27 · answer #1 · answered by Dr Dave P 7 · 0 0

acetone is non-electrolyte : if we have 0.1 mol in H2O since it does not dissociate we find 0.1 mol
HClO is a weak electolyte HClO <--> H+ + ClO- we find between 0.1 and 0.2 mol of solute particles
NH4Cl is a strong electrolyte : NH4Cl >> NH4+ + Cl- . We find 0.2 moles of solute particles

2007-07-25 15:16:11 · answer #2 · answered by Dr.A 7 · 0 0

Acetone, CH3CO.CH3, yields 0.1 mol particles, because it does not dissociate.

HClO <===> H+ + ClO+ incompletely ionized, so yields between 0.1 mol and 0.2 mol.

NH4Cl ===> NH4+ + Cl- so yields 0.2 mol particles

2007-07-25 15:12:59 · answer #3 · answered by steve_geo1 7 · 0 0

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