A candy dish contain 6 orange and 4 lime gumdrops. If 2 gumdrops are drawn from the dish at random, whats the

Question

probability that both gumdrops will be orange?

the answer is 1/3 .

is this found through the choose formula (nCr)? & can you show your work so i can understand it better? i forgot how to solve this

its from my SAT practice book you butt >:[ i'm taking the practice exam today so i'm studying for it. dont make false accusations

Answer 1

thr r two ways
firstly,thr r 6 orange gum drops and total r 10.so for first orange gum drop,probability=6/10.now one orange has been taken away.So orange left are 5 and total r 9.So probability of gettin second orange=5/9.
thrfore net probability =(6/10).(5/9)=1/3.
else use combination.
required probability= no. of ways of selecting 2 orange balls frm total 6 orange balls/no. of ways of selecting any two gumballs frm 10=6C2/10C2=1/3

Answer 2

There are 10 gumdrops altogether. 6 are orange so the prob of picking an orange one is 6/10 (or 3/5). 4 are lime so the prob of picking one is 4/10 (or 2/5)

After an orange gumdrop is picked there are 9 gumdrops, consisting of 5 orange (5/9 prob) & 4 lime (4/9)

to work out the overall probability you multiply the probability of getting an orange gumdrop on the first pick (3/5) by the probability of getting one on the second pick (5/9)

so... 3/5 x 5/9= 15/45 = 1/3

you don't use the nCr button because the probability doesn't stay constant. hope this helps

Answer 3

When you draw the first gumdrop, the probability that it will be orange is 6/(6+4) = 6/10.

When you draw the second gumdrop, there are 5 remaining oranges, so the probability that you get another orange is 5/(5+4) = 5/9.

The probability that you will get two oranges is just the product of these two probabilities.

Answer = (6/10)*(5/9) = 30/90 = 1/3

Answer 4

Just count.
The probability of the first gumdrop being orange is 6 out of 10
The probability of the second gumdrop being orange is 5 out of 9.
The combined probability is (6/10)*(5/9)=30/90=1/3

Answer 5

ok so theres 10 gumdrops....if you choose 1 out, it has a 60 percent chance of being orange, keep that one out, the next draw now has 9 gumdrops with 5 orange and would now be a chance of 5/9, therefore you take (6/10)(5/9) which equals .3333 or 1/3.

Answer 6

you have a 6/10 chance of picking your fist gumdrop orange... and a 5/9 of the second....multiply the two
that's a 30/90chance.

so....1/3


am i right ??? it's been so long.

Answer 7

P(A) = P( first is orange) = 6 / 10 = 3 / 5

P(B) is
P( second orange given 1st is orange) = 5 / 9

P(A) x P(B) = (3/5) x (5/9) = 1 / 3